Determining the name of a single file

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Barb_Texas

Posts: 10
Joined: Tue Dec 09, 2014 10:28 am

Post by Barb_Texas » Mon Jan 25, 2016 5:13 pm
I am trying to query to find out the file name that has been unzipped. We do it now from a file list, but I would like to query a directory that I know only has one file in it, for the file name.

In a list, we use the function Set Variable and assign the variable the results.
variable = ${ScanFile:name}
Where ScanFile is the current item variable.

I can only see how that is done in a LIST.
How can I assign a variable a file name if it is not being processed through a list?
Thank you,
B Smith

Support_Rick

Support Specialist
Posts: 592
Joined: Tue Jul 17, 2012 2:12 pm
Location: Phoenix, AZ

Post by Support_Rick » Mon Jan 25, 2016 6:33 pm
Barb,

You can get access to file information outside of a ForEach list (like you're indicating) by utilizing the "FileInfo" function.

Go into the Wizard for the assignment of a variable, then in the middle column, select "FileInfo" then utilize that to retrieve any information about a file provided as a "string" variable a input to the function.

This should give you what you're looking for.
Rick Elliott
Lead Solutions Consultant
(402) 944.4242
(800) 949-4696

Barb_Texas

Posts: 10
Joined: Tue Dec 09, 2014 10:28 am

Post by Barb_Texas » Thu Jan 28, 2016 5:27 pm
Thank you Rick. I will try this.
3 posts Page 1 of 1